Compound Probability Worksheets 7th Grade

📆 Updated: 1 Jan 1970
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🔖 Category: 7th Grade

Are you a 7th grade teacher or parent in search of engaging and informative resources to help your students understand compound probability? Look no further than these worksheets! Designed specifically for 7th grade learners, these worksheets focus on reinforcing the fundamental concepts of compound probability in a clear and accessible manner.



Table of Images 👆

  1. Probability Worksheets 7th Grade Math
  2. Probability Worksheets 7th Grade Math
  3. 7th Grade Math Worksheets
  4. 8th Grade Math Worksheets Ratios
  5. Compound Events Probability Word Problems
  6. 7th Grade Skeletal System Study Guide
  7. Probability Scale Worksheet
  8. 8th Grade Math Worksheets Printable
  9. 7th Grade Math Worksheets Proportions
  10. 7th Grade Language Arts Worksheets
  11. Complementary Supplementary Angles Worksheet 7th Grade
  12. Compound Probability Worksheet 7th Grade
Probability Worksheets 7th Grade Math
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Probability Worksheets 7th Grade Math
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7th Grade Math Worksheets
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8th Grade Math Worksheets Ratios
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Compound Events Probability Word Problems
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7th Grade Skeletal System Study Guide
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Probability Scale Worksheet
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8th Grade Math Worksheets Printable
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7th Grade Math Worksheets Proportions
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7th Grade Language Arts Worksheets
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Complementary Supplementary Angles Worksheet 7th Grade
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Compound Probability Worksheet 7th Grade
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What is compound probability?

Compound probability refers to the likelihood of two or more events occurring together in a sequence or at the same time. It involves combining the probabilities of individual events to determine the overall likelihood of the compound event. This type of probability calculation is important in various fields such as mathematics, statistics, and decision-making processes.

What is the probability of tossing a coin and rolling a number greater than 4 on a standard six-sided die?

The probability of tossing a coin and rolling a number greater than 4 on a standard six-sided die is 1/2 for the coin toss (since there are two possible outcomes - heads or tails) and 1/3 for rolling a number greater than 4 on a six-sided die (since there are two numbers that satisfy the condition out of six possible numbers). Multiplying these probabilities together, the overall probability would be 1/6.

If a bag contains 5 red and 3 blue marbles, what is the probability of selecting a red marble and then a blue marble without replacement?

The probability of selecting a red marble first is 5/8, and then a blue marble second is 3/7. To find the combined probability, we multiply the individual probabilities together: (5/8) * (3/7) = 15/56. Therefore, the probability of selecting a red marble followed by a blue marble without replacement is 15/56.

A deck of cards has 26 red cards and 26 black cards. What is the probability of drawing a red card, replacing it, and then drawing a black card?

The probability of drawing a red card on the first draw is 26/52, which simplifies to 1/2. Since the card is replaced, the probability of drawing a black card on the second draw is also 26/52 or 1/2. To find the probability of both events occurring, we multiply the probabilities together: 1/2 * 1/2 = 1/4. Therefore, the probability of drawing a red card and then a black card is 1/4.

If the chance of winning a game is 3/5 and the chance of losing is 2/7, what is the probability of winning and then losing?

To find the probability of winning and then losing, you multiply the probabilities of each event occurring sequentially. So, the probability of winning and then losing would be (3/5) * (2/7) = 6/35.

A jar contains 10 green, 7 blue, and 3 yellow candies. What is the probability of selecting a green candy, replacing it, and then selecting a blue candy?

The probability of selecting a green candy is 10/20, as there are 10 green candies out of a total of 20 candies. Since the candy is replaced after the first selection, the probability of selecting a blue candy after selecting a green candy is 7/20, as there are 7 blue candies remaining out of a total of 20 candies. Therefore, the probability of selecting a green candy and then a blue candy is (10/20) * (7/20) = 0.175 or 17.5%.

If two fair six-sided dice are rolled, what is the probability of rolling a sum of 7 and then rolling a sum greater than 10?

The probability of rolling a sum of 7 with two fair six-sided dice is 6/36, or 1/6. To calculate the probability of rolling a sum greater than 10 after rolling a sum of 7, we need to consider the outcomes for the second roll that would satisfy this condition. The only possible outcomes that would result in a sum greater than 10 are rolling a 5 and a 6, or rolling a 6 and a 5. Each of these outcomes has a probability of 1/36. Therefore, the overall probability of rolling a sum of 7 and then rolling a sum greater than 10 is (1/6) * (1/36) * 2 = 1/216.

In a deck of cards, there are 12 face cards and 40 non-face cards. What is the probability of drawing a face card and then drawing a non-face card without replacement?

The probability of drawing a face card on the first draw is 12/52. After drawing a face card, there are 39 non-face cards left out of the remaining 51 cards. Therefore, the probability of drawing a non-face card on the second draw is 39/51. To find the total probability of both events happening, we multiply the individual probabilities together: (12/52) * (39/51) = 13/102, which simplifies to approximately 0.127.

A box contains 8 red, 4 blue, and 6 green socks. What is the probability of selecting a red sock, replacing it, and then selecting a green sock?

The probability of selecting a red sock from the box is 8/18. Since the red sock is replaced before selecting a green sock, the probability of selecting a green sock is 6/18. Therefore, the probability of selecting a red sock and then a green sock is (8/18) * (6/18) = 4/27.

If the probability of eating breakfast is 3/7 and the probability of eating lunch is 4/7, what is the probability of eating breakfast and then lunch?

The probability of eating breakfast and then lunch is the product of the individual probabilities, which is (3/7) * (4/7) = 12/49.

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